Saturday, September 3, 2011

Swimming in the Pool: Distance and Displacement

me entering the pool
Today, I went swimming in my pool. I began by the steps on the right of the picture and swam to the end of the pool on the left. I count one lap as going to the end and coming back. After I did five laps in the pool I got out.  I started at about 4:55 and stopped at 4:57 with 10 seconds left.  So it took 130 seconds.  The length of my pool is about 27 feet, or 9 meters.  In physics, I learned that distance is the magnitude, or the amount of the displacement.  Therefore, one total lap is equal to 9m*2, and 5 laps is equal to 5(9m*2), which is equal to 90 meters.  Since I calculated the distance, I can plug it in to the formula we learned in class for average speed.  The formula is distance/time=speed. 90 meters/130 seconds=.69 m/s. So I swam about .69 meters per second.

I could also use this data to find my average velocity. We learned that the formula for average velocity is: displacement/time=velocity.  Displacement differs from speed because it is the "shortest path from the initial to the final position of the object's motion." In order to find my displacement, I used the formula: x final-x initial=displacement.  Therefore, the displacement for one lap is equal to 9m - 9m=0m +/- .  0m/130 seconds=0 m/s +/- . My average velocity is 0 because I had 0 displacement due to just swimming back and forth.

Physics taught me that velocity is different from speed because velocity includes the speed and direction of the object's motion.  Swimming laps in the pool proves that speed and velocity are different. By finding the length of the pool and the time it took to swim 5 laps, I was able to gather the data necessary to calculate both speed and velocity.

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